Bi-Elliptic Transfer Calculator
Compare a three-burn bi-elliptic transfer against a standard Hohmann transfer to find the most fuel-efficient maneuver.
Understanding Bi-Elliptic Transfers
A bi-elliptic transfer is a three-burn orbital maneuver that can be more fuel-efficient than a Hohmann transfer when moving between orbits with a very large radius ratio. While counterintuitive, traveling farther by swinging out to a high intermediate orbit before returning to the target orbit can actually save propellant.
The Three-Burn Sequence
The maneuver consists of three distinct engine firings:
- Burn 1: At the starting orbit, accelerate into the first elliptical transfer orbit aimed at the high intermediate apoapsis.
- Burn 2: At the intermediate apoapsis (r3), fire again to transition into the second transfer ellipse targeting the final orbit.
- Burn 3: At the target orbit radius, circularize into the desired final orbit.
The Bi-Elliptic Formulas
Using the semi-major axes of the two transfer ellipses a1 = (r1+r3)/2 and a2 = (r2+r3)/2:
Δv1 = √(2μ/r1 - μ/a1) - √(μ/r1)
Δv2 = √(2μ/r3 - μ/a2) - √(2μ/r3 - μ/a1)
Δv3 = √(μ/r2) - √(2μ/r2 - μ/a2)
The 11.94× Rule
The critical threshold is an orbit ratio of approximately 11.94. Below this ratio, a Hohmann transfer is always more efficient. Above this ratio, a properly chosen bi-elliptic transfer saves fuel. Between 11.94 and 15.58, the savings depend on how high the intermediate orbit is placed. Above 15.58, a bi-elliptic transfer always wins regardless of the intermediate orbit choice.
Trade-offs
The primary disadvantage of bi-elliptic transfers is time. The spacecraft must travel much farther, resulting in significantly longer transit times. For crewed missions, where life support and cosmic radiation exposure are concerns, the time penalty often outweighs the fuel savings. For robotic missions or when minimizing fuel consumption is paramount, bi-elliptic transfers are a powerful option.